- #1
aurao2003
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Homework Statement
When a car is speeding over a curved surface e.g a bridge, it sometimes loses contact with the ground. We have seen this many times in high speed chases and rally driving.
In this scenario, the textbook wrote this equation:
S-mg =Mv^2/r
The RHS side is obviously the equation for centripeta force (F=Mv^2/r).
But why is the resultant force S-mg since S=0? I thought the only relevant force should be the weight which acts downwards thereby forcing the car back on to the road. Also in the context of the centripetal force, is it not the weight that acts as the centripetal force in this case. Therefore I was thinking the equation should be
mg =mv^2/r.