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gtn013
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Homework Statement
At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders "plastered against the wall. Suppose the radius of the room is 3.30 m and the speed of the wall is 10.0 m/s when the floor falls away. What is the minimum coefficient of static friction that must exist between a rider's back and the wall, if the rider is to remain in place when the floor drops away if the rider has a mass of 55 kg?
Homework Equations
Centripetal Force = mv^2/r = 1667
friction = u*Fn
The Attempt at a Solution
centripetal force = friction = coefficient of friction * Normal Force
Normal force = mg (weight)
coefficient of friction = centripetal force/Normal Force = 51.5?
Is this correct?