- #1
quietrain
- 655
- 2
hi does anyone know why the 2nd derivative chain rule is as such?
i roughly know that
if u = f(x,y) and x=rcos(T) , y = rsin(T)
then
du/dr = df/dx * dx/dr + df/dy * dy/dr
but if i am going to have a second d/dr, then how does it work out?
i roughly know that
if u = f(x,y) and x=rcos(T) , y = rsin(T)
then
du/dr = df/dx * dx/dr + df/dy * dy/dr
but if i am going to have a second d/dr, then how does it work out?