- #1
dratcliff
- 6
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Hi, I just popped into see if there are any budding young engineers here (hope I got the right forum) interested in helping with a problem that I have been nutting out over the years... Hope your forum can help.
It is all about controlling sway and buckling of members and gaining the full compressive strength of materials... steel in particular.
My theory is that... If, provided that you could artificially control against buckling and swaying, steel has the ability to withstand almost 4,000 metres in height (uniform section) before it crushes from its own self weight/gravity... So, if we can control against sway and buckling with a type of webbing, and depending on the weight of the webbing (maybe down to 10% of the core weight), a uniform steel tower should reach a height of around 3,500 metres (tapered 7,000 metres).
I have started a thread on a catapult forum posing the question/challenge, so if anyone is interested in joining in and solving the problem, I would welcome your input.
http://www.thehurl.org/tiki-view_fo...mode=commentDate_desc&topics_find=&forumId=2"
With thanks,
David
(If you have any questions I will reply here if you like)
It is all about controlling sway and buckling of members and gaining the full compressive strength of materials... steel in particular.
My theory is that... If, provided that you could artificially control against buckling and swaying, steel has the ability to withstand almost 4,000 metres in height (uniform section) before it crushes from its own self weight/gravity... So, if we can control against sway and buckling with a type of webbing, and depending on the weight of the webbing (maybe down to 10% of the core weight), a uniform steel tower should reach a height of around 3,500 metres (tapered 7,000 metres).
I have started a thread on a catapult forum posing the question/challenge, so if anyone is interested in joining in and solving the problem, I would welcome your input.
http://www.thehurl.org/tiki-view_fo...mode=commentDate_desc&topics_find=&forumId=2"
With thanks,
David
(If you have any questions I will reply here if you like)
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