Challenge where you have to make each number from four 4s

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  • Thread starter Joffe
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In summary: 23 = 4!-4^4+4!.443 = 4!+.4^4+4!46 = 4!/4+4!.4-4...but i am missing a few others. i think i need 3 more. i will try to find them. if someone else can find them first, you are welcome to try. i will also show it to my teacher. she is the one who gave me the idea. she will be interested to see it once i have completed it. i will post it here once i have done so. i am not sure if i will be able to do so today. i will be busy tomorrow and
  • #36
Let ! be the operator such that x! = 89.x/(4+4+4+4)

Therefore

89 = (4+4+4+4)!

When we apply arbitrary rules to what mathematics "means" and when an answer is "right" or "wrong", then it isn't really mathematics any more, it is more like politics or accountancy!
 

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