Challenging Physics problem of the week. Do as much as you can. Thanks

  • Thread starter Thread starter geo951
  • Start date Start date
  • Tags Tags
    Physics Thanks
Click For Summary
Tom Jager's average speed for swimming 50 meters in 21.81 seconds is calculated to be 2.29 m/s. To determine how long it would take him to swim one mile at this pace, users are advised to convert miles to meters and apply relevant kinematic equations. The discussion also includes a comparison between Jager and Michael Phelps, who swims at an average speed of 2.35 m/s, prompting calculations to determine the winner of a 50-meter race. Additionally, the acceleration of a car from 0-60 mph in 2.7 seconds is analyzed, with requests for calculations in both (mi/h)/s and m/s². Participants are encouraged to show their attempts at solving the problems rather than seeking complete solutions.
geo951
Messages
2
Reaction score
0

Homework Statement



1. Tom Jager swam the 50 m free in 21.81 seconds.

a. Calculate Tom's average speed
b. If Tom could continue this incredible pace, how long (in minutes) would it take him to swim one mile?
c. Tom races Micheal Phelps. If Phelps swims at an average of 2.35 m/s and the race is 50 meters in length, who wins and by what distance?

2. A car can accelerate from 0-60 mph in 2.7 seconds.

a. Calculate the average acceleration of this car in (mi/h)/s and in m/s^2
b. How fast will the car be traveling after 1.65 seconds
c. How long would it take the car to accelerate from 10 mi/h to 35 mi/h?
 
Physics news on Phys.org
Hi geo951,
Welcome to PF.
We are here to help the students in their home work difficulties, not receive the challenges. If you have any difficulties in the above problems, show your attempts.
 
1a. 50m/21.81= 2.29 m/s

I just need help on how to do the rest. You do not have to do it all for me.
 
geo951 said:
1a. 50m/21.81= 2.29 m/s

I just need help on how to do the rest. You do not have to do it all for me.
Write down the relevant kinematic equations. Find the conversion of mile to meter.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
13
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
10
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
7K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K