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Lolagoeslala
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Homework Statement
an object of mass 750 kg is lifted from the Earth's surface to a height of 6.8 x 10^6 m above its surface. Calculate the change in gravitational potential energy for the object.
The Attempt at a Solution
I used this formula ΔEg = Eg2 - Eg1
ΔEg = -(GMm/r2) - (-GMm/r1)
Eg2 = -(GMm/r2)
Eg2 = -(6.67x10^-11 Nm^2/kg^2)(5.98 x10^24kg)(750kg)/(6.8x10^6m)+(6.37x10^6m)
Eg2 = -2.27 x 10^10 J
Eg1 = -(GMm/r1)
Eg1 = -(6.67x10^-11 Nm^2/kg^2)(5.98 x10^24kg)(750kg)/(6.37x10^6m)
Eg1 = -4.7x 10^10 J
ΔEg = Eg2 - Eg1
ΔEg = -2.27 x 10^10 J + 4.7x 10^10 J
ΔEg = 2.43 x 10^10 J
Is my process correct?