- #1
vkash
- 318
- 1
change in internal energy is a function of temperature. So if there is no change in temperature then there should no change in internal energy.
But consider this example.
work done(W)= nRT*ln(P1/P2) (Δ)T=0; so it's isothermal)
heat supplied(Q)=0 (No heat is supplied, gas expand by force on piston of it's own pressure)
change in internal energy=Q-W (using Q=U+W)
So from here we come to know that change in internal energy is not zero. But there is no change in temperature during the whole process so change in internal energy should zero...
So where am i getting it wrong.?
thanks!
But consider this example.
work done in processA gas is at 20 atm pressure in a room whose pressure is 1 atm.using external forces(on piston). Gas slowly expands its volume till it's pressure became 1 atm.during the process the temperature is maintained at 278K(room temperature).
work done(W)= nRT*ln(P1/P2) (Δ)T=0; so it's isothermal)
heat supplied(Q)=0 (No heat is supplied, gas expand by force on piston of it's own pressure)
change in internal energy=Q-W (using Q=U+W)
So from here we come to know that change in internal energy is not zero. But there is no change in temperature during the whole process so change in internal energy should zero...
So where am i getting it wrong.?
thanks!