- #1
drewcila
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OP warned about not using the homework template
The question is to find the change in kinetic energy of a system. the system in use is a pully system with a wooden block on a flat surface attached to a 100g mass. I have calculated force of friction between the block and desk, and using a ticker timer, I have individual speeds at every 0.1 of a second. Additionally, the distance it travels is 45cm. We have to prove that the change in Kinetic energy is = work done in the system, so I can't use work as my answer.
I know that the equation for kinetic energy is Ek= 1/2mv2
Change in Kinetic energy is represented by the final Ek - initial Ek
I was thinking something like Ekf = 1/2(0.100)v22
then subtract Eki= 1/2(0.100)v12
I do not know what variables to use in this situation. do I use the mass of the block or the 100g mass apply force? and which velocity should I use? the speed at 0.1 seconds and 0.6 seconds? Does friction play into kinetic energy?
I know that the equation for kinetic energy is Ek= 1/2mv2
Change in Kinetic energy is represented by the final Ek - initial Ek
I was thinking something like Ekf = 1/2(0.100)v22
then subtract Eki= 1/2(0.100)v12
I do not know what variables to use in this situation. do I use the mass of the block or the 100g mass apply force? and which velocity should I use? the speed at 0.1 seconds and 0.6 seconds? Does friction play into kinetic energy?