Change in the magnitude of the ball's momentum.

[superjen]

A 204g ball falls vertically downward, hitting the floor with a speed of 2.57 m/s and rebounding upward with a speed of 2.10 m/s. Calculate the magnitude of the change in the ball's momentum.
Answer: 9.53E-01 kg*m/s


Calculate the change in the magnitude of the ball's momentum.

i really don't know how to go about the the second question. Any help? or tips?

 

[rl.bhat]

If you want to find the change in momentum taking into consideration the magnitude and direction what will be the answer?

 

[nlightner]

To calculate the change in the magnitude of the ball's momentum, you can use the formula:

Change in momentum = final momentum - initial momentum

In this case, the final momentum is the momentum of the ball after it rebounds upward, and the initial momentum is the momentum of the ball before it hits the floor.

To find the final momentum, you can use the formula:

Final momentum = mass * velocity

The mass of the ball is given as 204g, which is equivalent to 0.204kg. The velocity of the ball after it rebounds upward is 2.10 m/s.

Therefore, the final momentum = 0.204kg * 2.10 m/s = 0.4284 kg*m/s

To find the initial momentum, you can use the same formula but with the initial velocity of the ball, which is 2.57 m/s.

Therefore, the initial momentum = 0.204kg * 2.57 m/s = 0.52578 kg*m/s

Now, to calculate the change in momentum, we can subtract the initial momentum from the final momentum:

Change in momentum = 0.4284 kg*m/s - 0.52578 kg*m/s = -0.09738 kg*m/s

However, since the question asks for the magnitude of the change in momentum, we need to take the absolute value of the answer, which is 0.09738 kg*m/s.

Therefore, the magnitude of the change in the ball's momentum is 0.09738 kg*m/s or 9.53E-01 kg*m/s in scientific notation.