Charge density and potential in a semiconductor

Finally, use the charge densities to plot the potential V as a function of position and find the strength of the electric field at the midplane.
  • #1
Gogsey
160
0
Couple of electricity questions here.

4. (a) Show that in a steady state, any isotropic material that obeys Ohm’s Law contains
no regions with net charge.
(b) In certain types of anisotropic materials, the conductivity  is not a scalar but
instead a tensor that can be represented as a symmetric 3x3 matrix; any such
tensor can be rotated into a frame of reference in which it is diagonal, i.e. only the
diagonal components are non-zero. Assuming this frame of reference, calculate
the divergence of J in the material in terms of the components of  and the
components of the electric field. Is such a material also guaranteed to be free of
regions of net charge? If so, why? If not, give a counterexample.

5. In a silicon junction diode, the region of the planar junction between n-type and p-type
semiconductors can be approximately represented as two adjoining slabs of charge, one
negative and one positive. Away from the junction, outside these charge layers, the
potential is constant, with a value of Vn in the n-type material and Vp in the p-type
material. Given that the difference between Vp and Vn is 0.3 V, and that the thickness
of each of the two slabs of charge is 0.01 cm, find the charge density in each of the
two slabs, and make a graph of the potential V as a function of position through the
junction. What is the strength of the electric field at the midplane?


For the top one, we know that the material is uniform in propreties throughout the material. We aso know that in the steady state, the charges density is constant. Either rate in + rate out, or the is nom flow of electrons and there for the material is electrically neutral.

So charge density is constant, then, then its divergence is zero. Now we know thw conservation of charge is "del" J = -dp/dt. Do we just have to proove that both sides are zero, since they are both constant? Therefore charge density never changes? Also, mathematically, do we just show that they are both zero, and that's good enoough?

For the second question, we can use Gauss' law to get an expression of the field, but we don't know the charge. We can integrate potential twice to get the charge, but we on;y have a number not a function. Can we integrate the number twice with respect to t, just as we would do with gravity to get 1/2 gt^2, or in this case 0.3/2t^2?
 
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  • #2
For 4(a), write Ohm's law in the form [itex]\vec{J}=\sigma\vec{E}[/itex]. What do you get when you take the divergence of each side of the equation? :wink:

For 4(b), [itex]J_i=\delta_{ij}(\sigma_{ij}E_j)[/itex] and [itex]\vec{\nabla}\cdot\vec{J}=\partial_iJ_i[/itex]

For 5, Use gauss' law to get an expression for the fields in n and p type materials in terms of the two unknown charge densities [itex]\sigma_{-}[/itex] and [itex]\sigma_{+}[/itex] assume that the charge densities are constant and integrate the fields over the thickness of each slab to find an expression for the potential difference. Then set that equal to 0.3V and assume that the overall charge on the junction is zero, so that [itex]\sigma_{+}=-\sigma_{-}[/itex] and solve for the charge densities.
 

FAQ: Charge density and potential in a semiconductor

1. What is charge density in a semiconductor?

Charge density in a semiconductor refers to the amount of electric charge per unit volume of the semiconductor material. It is typically measured in units of coulombs per cubic meter (C/m^3) and is dependent on the number of charge carriers (electrons or holes) present in the material.

2. How does charge density affect the properties of a semiconductor?

The charge density in a semiconductor has a significant impact on its electrical properties. It determines the conductivity of the material and affects the formation of depletion regions, which play a crucial role in the operation of semiconductor devices such as diodes and transistors.

3. What is the relationship between charge density and potential in a semiconductor?

The charge density and potential in a semiconductor are closely related. The potential is a measure of the energy required to move a unit of charge from one point to another within the material. As the charge density changes, so does the potential, and vice versa.

4. How is charge density and potential measured in a semiconductor?

Charge density and potential can be measured using various techniques, such as Hall effect measurements and capacitance-voltage measurements. These methods involve applying an external electric field or voltage to the semiconductor and measuring the resulting changes in charge density and potential.

5. How can charge density and potential be controlled in a semiconductor?

The charge density and potential in a semiconductor can be controlled through the use of doping, which involves intentionally introducing impurities into the material to alter its electrical properties. Additionally, applying an external electric field or voltage can also manipulate the charge density and potential in a semiconductor.

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