- #1
GravityGirl
- 29
- 0
Three capacitors of capacitance 5, 7, and 2 mF respectively, are connected in series to a 1 V battery. What is the charge on the positive plate of the 7 mF capacitor?
so if the capacitors are all connected to the battery... than all of them have to have a electrial potential of 1 v
since C=Q/V, then CV=Q
and then i have (7 x10^-6 F)*1V=Q which is 7x10^-6 C
that is what i am getting, but it seems to be wrong. please help me out
so if the capacitors are all connected to the battery... than all of them have to have a electrial potential of 1 v
since C=Q/V, then CV=Q
and then i have (7 x10^-6 F)*1V=Q which is 7x10^-6 C
that is what i am getting, but it seems to be wrong. please help me out