Sure. Do you expect something else?brianeyes88677 said:Will this system become stable?
Yes, this is given by charge conservation.brianeyes88677 said:This is not a homework, it's just a concept that flash through my mind. If it is a capacitor just like you say, the amount of charges on the two spheres should be the same
Where is the problem?brianeyes88677 said:how can it be stable if the amount of charges are the same?
The equation for finding the charge on two concentric spherical shells is Q = (4πε0)(R1 - R2)Φ, where Q is the total charge, ε0 is the permittivity of free space, R1 is the radius of the larger shell, R2 is the radius of the smaller shell, and Φ is the electric flux through the region between the two shells.
The charge distribution on the two shells affects the electric field between them by creating a radial electric field that points from the larger shell to the smaller shell. The magnitude of the electric field is directly proportional to the charge on each shell and inversely proportional to the distance between them.
If the two shells have the same charge, the electric field between them will be zero. This is because the electric fields created by each shell will cancel each other out, resulting in a net electric field of zero.
Yes, it is possible for the charge distribution on the two shells to be different and still have a net electric field of zero. This can occur if the smaller shell has a higher charge density than the larger shell, resulting in a stronger electric field from the smaller shell that cancels out the electric field from the larger shell.
The distance between the two shells does not directly affect the charge on each shell. However, as the distance between the two shells increases, the electric field between them decreases, which can result in a redistribution of charge on the two shells. This is because the charges on the shells will repel each other and move to positions that result in a lower overall electric field between them.