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SherlockOhms
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Homework Statement
A capacitor is charged up to it's maximum charge capacity. Once it's reached it's maximum charge capacity, a switched is open which isolates the charged capacitor in a circuit of it's own, containing itself and a resistor (The emf used to charge the capacitor is no longer involved). Draw a rough graph outlining the current in the isolated loop's behaviour with respect to time.
Homework Equations
The Attempt at a Solution
Well, as the capacitor discharges, the current will increase to a maximum value and then eventually die off after the capacitor has fully discharged due to there being no emf to drive the current around the circuit. So, the graph would look something like a hill. Sort of going up (I increasing) and eventually going down ( I decreasing). Does this sound correct?