- #1
angel23
- 21
- 0
find convolution of.
n+1 0<=n<=2
x[n]=
0 otherwise
h[n]= a^n u[n]
solution:
y[n]= a^n + 2a ^n-1 + 3 a^n-2
is it right?
n+1 0<=n<=2
x[n]=
0 otherwise
h[n]= a^n u[n]
solution:
y[n]= a^n + 2a ^n-1 + 3 a^n-2
is it right?