- #1
lemon
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1. If sinA=7/25 and sinB=5/13, where A is acute and B is obtuse, find the exact value of tan(A+B)
2. Tan(A+B)=tanA+tanB/1-tanAtanB
3. TanA=7/24
TanB=5/-12
Tan(A+B)=7/24+5/-12/1-7/24x5/-12=-36/323 or -0.1 (1d.p.)
Could somebody please check this for me, please?
2. Tan(A+B)=tanA+tanB/1-tanAtanB
3. TanA=7/24
TanB=5/-12
Tan(A+B)=7/24+5/-12/1-7/24x5/-12=-36/323 or -0.1 (1d.p.)
Could somebody please check this for me, please?