Chemistry Equations: Balancing Au2(SO4)3 + Ba and Determining Reaction Type"

[lexi]

Please help!

1. Homework Statement [/b
- I need to complete and balance Au2(SO4)3 + Ba ------>
- what type of reaction is this?
is this a redox reaction?
will the reaction go from left to right?

Homework Equations

The Attempt at a Solution

2Au+ 3SO4 + Ba?

 

[chemisttree]

If the reaction does occur (I don't have the electric potentials of Au and Ba handy) it is indeed a redox reaction. Barium replaces gold...

Write out the half cell reactions for Au+3 and Ba and go from there. Treat the sulfate as a spectator ion.

 

[Blueshift5]

To balance the equation Au2(SO4)3 + Ba ----->, you need to first determine the number of atoms for each element on both sides of the equation. In this case, there are 2 Au atoms, 3 S atoms, 12 O atoms, and 1 Ba atom on the left side, and 1 Au atom, 1 S atom, and 1 Ba atom on the right side. To balance the equation, you will need to add coefficients in front of the compounds to ensure that the number of atoms for each element is equal on both sides. The balanced equation would be: 2Au2(SO4)3 + 3Ba -----> 4Au + 3Ba(SO4)2.

As for the reaction type, this is a double displacement reaction, also known as a metathesis reaction, where two compounds switch partners to form two new compounds. In this case, Au2(SO4)3 reacts with Ba to form Au and Ba(SO4)2.

This is not a redox reaction because there is no change in oxidation state for any of the elements involved. And as for the direction of the reaction, it is not possible to determine without additional information such as the concentration and temperature of the reactants.