- #1
Ly444999
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So I just had a question about calculating moles atomic iodine when you have the moles of molecular iodine. In the chemical equation IO3-(aq) + I-(aq) + H+(aq) = I2(aq) + H2O(l)
Would the moles of atomic iodine be equal to the moles of the molecular iodine? or would the moles of atomic iodine be twice as much as molecular iodine?
Edit: Just realized the equation is unbalanced:
IO3-(aq) + 5I-(aq) + 6H+(aq) = 3I2(aq) + 3H2O(l)
Would the moles of atomic iodine be equal to the moles of the molecular iodine? or would the moles of atomic iodine be twice as much as molecular iodine?
Edit: Just realized the equation is unbalanced:
IO3-(aq) + 5I-(aq) + 6H+(aq) = 3I2(aq) + 3H2O(l)
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