- #1
bartlino
- 3
- 0
Hello,
If I am trying to calculate the heat removed from a chiller system through this formula on engineering toolbox.com:
Does COP or efficiency of the equipment come into play with this calculation? For example if a chiller is fully loaded isn't it running more efficient for a watt/ton basis? Vs a chiller only running at 50% load, would COP be different?
I am interested in converting the btu/hr output to kW to attempt to relate this to the total electrical power (kW) consumption for a building.
Thanks!
If I am trying to calculate the heat removed from a chiller system through this formula on engineering toolbox.com:
Does COP or efficiency of the equipment come into play with this calculation? For example if a chiller is fully loaded isn't it running more efficient for a watt/ton basis? Vs a chiller only running at 50% load, would COP be different?
I am interested in converting the btu/hr output to kW to attempt to relate this to the total electrical power (kW) consumption for a building.
Thanks!