Circuit Analysis: Understand V2 & 3amp Equation

In summary, the conversation discusses a circuit with a 2Ω resistor and a 1Ω resistor, and the current through both. The main focus is on finding the linear equation to determine the current through the 2Ω resistor. KCL is suggested as a method to find the current through the bottom wire, which is a combination of the 2Ω and 1Ω resistors. The conversation concludes with a question about the linear equation for the junction under I2.
  • #1
fran1942
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0
Hello, I have tried really hard to understand this circuit but I just can't grasp it.

I am trying to understand how V2 comes to 6 volts ie. where does the 3amp come from that is multiplied by the value of V2 to give 6 volts.
It would help a lot if I could see the linear equation which gives 3 amps for the relevant loop.

Thanks kindly for any help with this.
 

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  • #2
hello fran1942! :smile:

use KCL to find the current through the bottom wire, directly under the 2Ω …

how much is that, and how does it help you to find the current through the 2Ω itself? :wink:
 
  • #3
OK thanks. I see that current will be the combination of the 2 and the 1, making 3. Is it as simple as that ?

The main thing bugging me was that I could not work out the linear equation to give that 3amps.
Could someone please help with that equation.

Thanks again.
 
  • #4
fran1942 said:
… I could not work out the linear equation to give that 3amps.

not following you …

the KCL linear equation for that junction under I2 is 1 + 2 = 3 …

what is worrying you about that? :confused:
 
  • #5


Hello,

I can understand your frustration in trying to understand this circuit. Let me try to explain it in a simpler way. In this circuit, V2 represents the voltage across a specific component or set of components. The 3amp refers to the current flowing through that component or set of components. The equation V2 = 6 volts is a result of Ohm's law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). In this case, the resistance is not explicitly given, but it is implied to be constant.

Therefore, we can write the equation as V2 = I x R. Since V2 is given as 6 volts and R is constant, we can solve for I by dividing both sides by R. This gives us the equation I = 6 volts/R. Since we know that V2 is equal to 3 amps, we can substitute that into the equation, giving us 3 amps = 6 volts/R. Solving for R, we get R = 6 volts/3 amps, which simplifies to R = 2 ohms.

In summary, the 3amp in the equation represents the current flowing through the component or set of components, and it is multiplied by V2 to give a voltage of 6 volts. This is a result of Ohm's law and the fact that the resistance in this circuit is 2 ohms.

I hope this explanation helps you understand the circuit better. Let me know if you have any further questions.
 

FAQ: Circuit Analysis: Understand V2 & 3amp Equation

What is circuit analysis?

Circuit analysis is a method used to analyze electrical circuits and understand the behavior of electrical components within a circuit.

What is V2 and 3amp equation in circuit analysis?

V2 and 3amp equation refers to the mathematical equation used to calculate the voltage and current in a circuit. It is given by V = IR, where V is voltage, I is current, and R is resistance.

Why is circuit analysis important?

Circuit analysis is important because it allows us to design and troubleshoot electrical circuits, ensuring that they function properly and safely. It also helps us understand the relationship between different components in a circuit.

What are the steps involved in circuit analysis?

The steps involved in circuit analysis include identifying the components and their values, determining the input and output of the circuit, applying Kirchhoff's laws and Ohm's law, and solving for the unknown variables using mathematical equations.

How does circuit analysis relate to real-world applications?

Circuit analysis is essential in various real-world applications, such as designing electronic devices, power systems, and communication systems. It is also used in industries like automotive, aerospace, and telecommunications to ensure the proper functioning of electrical circuits.

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