- #1
Master1022
- 611
- 117
- Homework Statement
- Convert the circuit into an equivalent resistance and a current source.
- Relevant Equations
- [itex] V = E - IR [/itex]
Picture of the circuit is posted below. Apologies, the voltage source on the left should read 24 V. My question is: What is wrong with this method? [Edit: Sorry if it wasn't clear- the method in the picture yields the wrong answer]
When I originally did the question, I just turned the LHS into its Norton equivalent and then combined to get the answer. However, why can't it be done this way as well (i.e. convert RHS to Thevenin equivalent, and then continue).
My initial thoughts have been to do with that we cannot combine the Thevenin equivalent in that way, but I was wondering why that would be the case?
When I originally did the question, I just turned the LHS into its Norton equivalent and then combined to get the answer. However, why can't it be done this way as well (i.e. convert RHS to Thevenin equivalent, and then continue).
My initial thoughts have been to do with that we cannot combine the Thevenin equivalent in that way, but I was wondering why that would be the case?
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