Circuit with two voltage sources (Kirchoff Rules)

[XianForce]

Homework Statement

The circuit shown in the figure below is connected for 3.10 min. (Assume R1 = 7.90 Ω, R2 = 2.60 Ω, and V = 16.0 V.)

The circuit shown in the figure below is connected for 3.10 min. (Assume R1 = 7.90 Ω, R2 = 2.60 Ω, and V = 16.0 V.)

Homework Equations

Kirchoff's Rules
V = IR

The Attempt at a Solution

So naming the current in the left segment I1 downwards, the current in the middle section I2 downwards, and the current in the right most section I3 upwards, I find from the junction rule that I1 + I2 = I3. Then using the current rule, I find that -16 +7.9 * I1 + 2.6 * I3 = 0. Substituting in I3 as I1 + I2, and then solving for I1 I find that I1 = (16 - 2.6I2) / 10.5 . Using the current rule again, I find that -4 + 7.9 * I1 - 6.0 * I2 = 0 and so I substitute for I1 and then solve for I2 to find that I2 = 1.0103. Then use that value back in other equations to find that I1 = 1.2736 Amperes downward, I2 = 1.0103 Amperes downward, and I3 = 2.2839 Amperes Upward.

Web Assign keeps saying these values are wrong and I have reworked these problems several times and keep getting the same answers.

 

[ehild]

Homework Statement

The circuit shown in the figure below is connected for 3.10 min. (Assume R1 = 7.90 Ω, R2 = 2.60 Ω, and V = 16.0 V.)

The circuit shown in the figure below is connected for 3.10 min. (Assume R1 = 7.90 Ω, R2 = 2.60 Ω, and V = 16.0 V.)

Homework Equations

Kirchoff's Rules
V = IR

The Attempt at a Solution

So naming the current in the left segment I1 downwards, the current in the middle section I2 downwards, and the current in the right most section I3 upwards, I find from the junction rule that I1 + I2 = I3. Then using the current rule, I find that -16 +7.9 * I1 + 2.6 * I3 = 0.

R2 is connected to a 3 ohm resistor in series.

ehild

 

[XianForce]

I cannot believe I missed that. Thank you!

 

[ehild]

I cannot believe I missed that. Thank you!

You are welcome.

ehild

 

[Nickie]

Can you please provide some feedback on what I may be doing wrong?


I would first suggest checking your calculations and making sure you have the correct values for the resistors and voltage source. Also, it is important to double check the direction of the currents in your equations. Additionally, make sure to use the correct units in your calculations. If you are still getting the same incorrect values, it is possible that there may be an error in the circuit diagram or in the given values. It may be helpful to consult with a classmate or your instructor for further assistance.