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albert4united
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Sorry if this is posted in the wrong area, I am relatively new.
Circular Motion Lab is set up like this to study circular motion:
http://docs.google.com/viewer?a=v&q=cache:lG3nvirsnOYJ:www.hwscience.com/Physics/regphysics/Lab%2520Handouts/Circ.%2520motion%2520LAB.pdf+circular+motion+hanging+mass&hl=en&gl=ca&sig=AHIEtbTBHCVNZxCFmkJyfcwpOLkbKJl59w
Rubber stopper is secured to string .4m long, and is spun horizontally and achieves period of 0.56275s. The hanging mass is 0.03kg. The mass of the stopper is unknown.
I figured out that Centripetal velocity is 4.466m/s.
The vertical forces is Fnet = Ft - Fg
Ft= Fnet + Fg
Ft = m(a + g)
Ft= 0.03 (9.81)
Ft= 0.2943
The horizontal forces are Fc = Ft
Fc= 0.2943 N !
Is this done RIGHT to FIND the centripetal FORCE of the rubber STOPPER?
Please explain if I am wrong...
Circular Motion Lab is set up like this to study circular motion:
http://docs.google.com/viewer?a=v&q=cache:lG3nvirsnOYJ:www.hwscience.com/Physics/regphysics/Lab%2520Handouts/Circ.%2520motion%2520LAB.pdf+circular+motion+hanging+mass&hl=en&gl=ca&sig=AHIEtbTBHCVNZxCFmkJyfcwpOLkbKJl59w
Rubber stopper is secured to string .4m long, and is spun horizontally and achieves period of 0.56275s. The hanging mass is 0.03kg. The mass of the stopper is unknown.
I figured out that Centripetal velocity is 4.466m/s.
The vertical forces is Fnet = Ft - Fg
Ft= Fnet + Fg
Ft = m(a + g)
Ft= 0.03 (9.81)
Ft= 0.2943
The horizontal forces are Fc = Ft
Fc= 0.2943 N !
Is this done RIGHT to FIND the centripetal FORCE of the rubber STOPPER?
Please explain if I am wrong...
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