Clarification of susskind lectures

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In summary, lecture 2 discusses the effects of applying a magnetic field on an electron. It is stated that when an electron is prepared and a magnetic field is applied, it can either emit no photon or one photon. The frequency of the emitted photon corresponds to the energy that would have been radiated if the electron was in the "north-down" position. The confusion arises when determining the direction of "up" and "down" for a single electron, as the electron never acts as if it is in between the two directions. It is clarified that "up" refers to the direction of the magnetic field and "down" is the opposite direction. When no photon is emitted, it is considered an "up" spin.
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Getterdog
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In lecture 2,he states that when we prepare an electron and then apply a magnetic field,only 2 things can happen, no photon,or 1 photon. " if a photon is emitted,then its frequency corresponds to the amount of energy that would be radiated if the electron had been prepared in the <north-down> position." Now if the photon can have only 1 energy , how do we now for a single electron what up or down is? I'm confused .
 
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"Up" is the direction the magnetic field is pointing, "down" is the opposite direction, and the interesting (and somewhat confounding) thing is that the electron never acts as if it's in between the two.
 
  • #3
Nugatory said:
"Up" is the direction the magnetic field is pointing, "down" is the opposite direction, and the interesting (and somewhat confounding) thing is that the electron never acts as if it's in between the two.
So you would say that when no photon is emitted that corresponds to an up spin?
 

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