- #1
greeziak
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I'm trying to show that for an electron of uniform charge and mass distributions spinning about a fixed axis that the classical calculation for the magnetic moment is
μs = -(e/2m)S where S is the spin angular momentum.
Now I know that the moment for any given current loop is μ = iA. So should I just be assuming all the charge is at the surface and integrate over the entire sphere? The moment for an orbiting electron is of the same form but with L instead of S, so I think this might be the way to start, but I'm not sure. Thanks.
μs = -(e/2m)S where S is the spin angular momentum.
Now I know that the moment for any given current loop is μ = iA. So should I just be assuming all the charge is at the surface and integrate over the entire sphere? The moment for an orbiting electron is of the same form but with L instead of S, so I think this might be the way to start, but I'm not sure. Thanks.