Classical magnetic dipole-dipole interaction in iron

In summary, you seem to have trouble understanding the physics of the dipole-dipole interaction in an ideal classical system. You have several doubts about how this system would work.
  • #1
rogdal
14
2
Homework Statement
A magnetic dipole μ, which is located at the origin of a coordinate system, generates a magnetic field in its environment given by:

$$\vec{B}(\vec{r})=\frac{\mu_0}{4\pi}\frac{3(\vec{\mu}·\vec{r})\vec{r}-r^2\vec{\mu}}{r^5}$$

Calculate the magnetic field B generated by an atom with a magnetic moment μ ≃ μB (Bohr magneton) at the position of a neighbouring atom in iron. The typical first-neighbour distance r0 for Fe ferromagnets can be calculated knowing that Fe has a bcc lattice with a = 2.866 ̊A.
Relevant Equations
$$\vec{B}(\vec{r})=\frac{\mu_0}{4\pi}\frac{3(\vec{\mu}·\vec{r})\vec{r}-r^2\vec{\mu}}{r^5}$$

In a BCC lattice, ##r_0 = \frac{\sqrt{3}}{2}a##
I'm having a bit of trouble with this exercise because, even if I understand the physics of the dipole-dipole interaction in an ideal classical system, I don't get to know how to approach this problem. I've got a few doubts about how this system would work.

First of all, what would be the direction of the magnetic moment ##\vec{\mu}## of iron with respect to its lattice? I guess that by simplicity the direction [100] should be chosen, but I don't know if each atom's magnetic moment has the same direction.

Besides, now assuming ##\vec{\mu}## is fixed, the value of B wouldn't be the same in all the first neighbours positions, right? Since it depends on the dot product between the magnetic moment and the first neighbour's position, and this wouldn't be the same for the atom in the upper left corner and the one in the bottom right.

Do you know how to approach this exercise?

Thank you!
 
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  • #2
You seem to worry about dipole-dipole interaction. But the problem states magnetic field caused by a dipole at the place of another dipole. You do not have to worry about the direction of the dipole at that place.
 
  • #3
anuttarasammyak said:
You seem to worry about dipole-dipole interaction. But the problem states magnetic field caused by a dipole at the place of another dipole. You do not have to worry about the direction of the dipole at that place.
Really? Well, in reality I worry about the direction of the dipole that is causing the magnetic field, i.e., the one in the origin of coordinates. Wouldn't its direction influence the product ##\vec{\mu}·\vec{r}##?
 
  • #4
rogdal said:
Wouldn't its direction influence the product μ→·r→?
Yes, the inner product matters. For an examle you may set r coordinates according to crystal structure and place a dipole in its origin and you can rotate dipole as you like which changes B at (1,0,0) for an example.

After you got it you may be able to proceed to next story of B##\mu_2## energy at (1,0,0) to estimate ##\mu_1## dipole-##\mu_2## dipole interaction.
 
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  • #5
anuttarasammyak said:
Yes, the inner product matters. For an examle you may set r coordinates according to crystal structure and place a dipole in its origin and you can rotate dipole as you like which changes B at (1,0,0) for an example.

But if I did what you say I'd have, for instance, ##\vec{r}=(1,0,0)##. Then the total magnetic field would be:

$$\vec{B}=\frac{\mu_0}{4\pi}\left(3(\mu\cos{\theta})\hat{u_x}-\vec{\mu}\right)$$

Since ##|\vec{r}|=1##. But this expression cannot be simplified because we don't know what the direction of ##\vec{\mu}## is.

Is that what you mean?

And then, I could get the dipole-dipole energy. But, assuming ##\vec{\mu_1}## and ##\vec{\mu_2}## are parallel, then their specific directions wouldn't be needed, right?

Thanks for the help!
 
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  • #6
It is also written as
[tex]\vec{B}(1,0,0)=\frac{\mu_0}{4\pi}(3\mu_x\hat{u_x}- \vec{\mu})[/tex]
##\vec{\mu}=(\mu_x,\mu_y,\mu_z)## is a parameter. It depends on direction of ##\vec{\mu}## as you suspect. Interaction energy with another dipole at (1,0,0) is
[tex]\vec{\mu_2}\cdot\vec{B}(1,0,0)=\frac{\mu_0}{4\pi}(3\mu_{1x}\mu_{2x}- \vec{\mu_1}\cdot\vec{\mu_2})[/tex]
 
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  • #7
Ah, I see. I thought the exercise was meant to obtain a well defined expression of ##\vec{B}## in terms of the Bohr magneton.

Thanks!
 
  • #8
It is interesting to look at the geometry and the minimum and maximum values (although usually one looks at energies rather than forces)
You do need to specify the relative orientation of the electron magnetic moments. Of course in a real chunk of iron the interaction of an electron spin with all of its neighbors is a very interesting problem that results in creation of self organizing magnetic domains. These magnetic domains are are also influenced by the geometry of the crystaline structure, not to mention the temperature (see Curie Temp) among other thinngs . Lotsa physics here.
 
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Related to Classical magnetic dipole-dipole interaction in iron

What is the classical magnetic dipole-dipole interaction in iron?

The classical magnetic dipole-dipole interaction in iron refers to the interaction between magnetic moments of iron atoms. This interaction is due to the magnetic field produced by one dipole affecting the magnetic field of another. It can be described by the dipole-dipole interaction energy, which depends on the distance and relative orientation of the dipoles.

How does the dipole-dipole interaction affect the magnetic properties of iron?

The dipole-dipole interaction significantly influences the magnetic properties of iron, such as its magnetization and magnetic ordering. It contributes to the alignment of magnetic moments, leading to phenomena like ferromagnetism, where magnetic moments align parallel to each other, resulting in a strong net magnetization.

What is the mathematical expression for the dipole-dipole interaction energy?

The dipole-dipole interaction energy \(E_{dd}\) between two magnetic dipoles \(\mathbf{m}_1\) and \(\mathbf{m}_2\) separated by a distance \(\mathbf{r}\) is given by the equation:\[ E_{dd} = \frac{\mu_0}{4\pi r^3} \left[ \mathbf{m}_1 \cdot \mathbf{m}_2 - 3 (\mathbf{m}_1 \cdot \hat{\mathbf{r}})(\mathbf{m}_2 \cdot \hat{\mathbf{r}}) \right], \]where \(\mu_0\) is the permeability of free space, and \(\hat{\mathbf{r}}\) is the unit vector along the line connecting the dipoles.

How does temperature affect the dipole-dipole interaction in iron?

Temperature affects the dipole-dipole interaction in iron by influencing the thermal agitation of magnetic moments. At higher temperatures, thermal energy can overcome the dipole-dipole interaction, leading to randomization of magnetic moments and a decrease in net magnetization. This is why iron loses its magnetic properties above its Curie temperature.

What role does the dipole-dipole interaction play in the formation of magnetic domains in iron?

The dipole-dipole interaction plays a crucial role in the formation of magnetic domains in iron. Magnetic domains are regions where the magnetic moments are aligned in the same direction. The dipole-dipole interaction helps to minimize the magnetic energy by aligning magnetic moments within a domain while reducing the magnetic field outside the domain, leading to a stable configuration of magnetic domains.

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