- #36
Fantasist
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DaleSpam said:This is incorrect. Since the moving clocks are (by design) synchronized in the stationary system they cannot be synchronized in the moving frame, regardless of what you might want.
The times in Einstein's synchronization equation for the stationary frame (assuming synchronized clocks in that frame)
tB' - tA1' = rAB/(c-v)
tA2' - tB' = rAB/(c+v)
are solely determined by the positions of the moving clocks and the light signal in that frame. How should the display of the moving clocks come into it? The latter might even stand still i.e. always display the same time, still the same equation would apply in the stationary frame, simply because a) only the positions of the moving clocks are timed, and b) these timings are obtained by a completely unrelated set of clocks.
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