- #1
Tertius
- 58
- 10
- TL;DR Summary
- The lapse function, or specifically ##g_{00} = N(t)## being a function of coordinate time, is often normalized away, ensuring proper time equals coordinate time.
In the ADM decomposition, like in the construction of the FRW metric, the coordinates are defined to be co-moving, so we know $$d\tau = dt$$ (i.e. the lapse function is normalized away)
Starting from a five-dimensional embedded hyperboloid (as in carroll pg. 324) ## -u^2 + x^2 + y^2 + z^2 + w^2 = \alpha^2 ##, constructing the 4D deSitter coordinates with ##{t, \chi, \theta, \phi}## I calculate that $$g_{tt} = cosh[\frac{2t}{\alpha}]$$
Yet in the derivation, Carroll simply removes it without even a mention of where it went. The code I wrote to generate the metric correctly produces the other 3 non-zero components, so I assume there is not an error. This would have generated a cyclic dependence of proper time on coordinate time.
The lapse function, which specifically dictates the temporal "distance" between spatial sub-manifolds, is ultimately seen as non-dynamic. And though it specifically applies to ADM decomposed spacetimes, it is physically saying that you can always find "co-moving" coordinates for ADM spacetimes.
Further, I found this proof that in general you can always find a co-moving reference frame for any spacetime. (https://www.zweigmedia.com/diff_geom/Sec11.html).
My first question is: why is it always possible (if that's actually true) to find a co-moving reference frame?
Observers are defined as a smooth section of the manifold. Such that ##g_{\mu\nu} = \eta_{ab} e^{a}_{\mu} e^{b}_{\nu}## where ##e## are the basis vectors. So.. by definition, an observer (who views the local spacetime as Minkowskian) will always have a proper time that matches coordinate time.
Second question: Does this concept of observers always viewing flat space locally (the equivalence principle) contain part of the reason why it is always possible to find co-moving coordinates?
Starting from a five-dimensional embedded hyperboloid (as in carroll pg. 324) ## -u^2 + x^2 + y^2 + z^2 + w^2 = \alpha^2 ##, constructing the 4D deSitter coordinates with ##{t, \chi, \theta, \phi}## I calculate that $$g_{tt} = cosh[\frac{2t}{\alpha}]$$
Yet in the derivation, Carroll simply removes it without even a mention of where it went. The code I wrote to generate the metric correctly produces the other 3 non-zero components, so I assume there is not an error. This would have generated a cyclic dependence of proper time on coordinate time.
The lapse function, which specifically dictates the temporal "distance" between spatial sub-manifolds, is ultimately seen as non-dynamic. And though it specifically applies to ADM decomposed spacetimes, it is physically saying that you can always find "co-moving" coordinates for ADM spacetimes.
Further, I found this proof that in general you can always find a co-moving reference frame for any spacetime. (https://www.zweigmedia.com/diff_geom/Sec11.html).
My first question is: why is it always possible (if that's actually true) to find a co-moving reference frame?
Observers are defined as a smooth section of the manifold. Such that ##g_{\mu\nu} = \eta_{ab} e^{a}_{\mu} e^{b}_{\nu}## where ##e## are the basis vectors. So.. by definition, an observer (who views the local spacetime as Minkowskian) will always have a proper time that matches coordinate time.
Second question: Does this concept of observers always viewing flat space locally (the equivalence principle) contain part of the reason why it is always possible to find co-moving coordinates?
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