- #1
tbone413
- 7
- 0
Homework Statement
An attraction at a waterpark includes a straight waterslide 20m long at an angle of 34 degrees above the horizontal. The waterslide ends in a ramp 5 m long at an angle of 45 degrees above the horizontal. People sliding down the slide land in a small pool just past the end of the ramp. The waterslide is kept frictionless by spraying fine streams of water onto it through several nozzles located along the length of the slide.
Unfortunately, a poor management decision to conserve water at the water park results in the water being turned off just as a 120 kg man enters the ramp, so that the last 5m of his trip on the slide is no longer frictionless. The man flies off the ramp, misses the pool and lands on the pavement a horizontal distance of 12m fro the end of the slide. What is the coefficient of friction between the man and the waterslide?
Homework Equations
F(x) = -Fk = ma(x)
F(y) = n - mg = 0
n-mgcos(theta) = 0
Ff(force of friction) + mgsin(theta) = ma(up)
The Attempt at a Solution
Well I am not really sure how to attempt this problem at all, its extra credit and we haven't quite learned this material yet. I do know though that its a Newtons second law problem and that when going up the ramp the frictional force will cause the acceleration to decrease. I also know that I have to use a FBD to figure out the acceleration and velocity of the man at the moment he hits the ramp, and then solve for the coefficient of friction. However I am not quite sure what steps to take. So if someone could maybe walk me through their thought process id Really appreciate it.