- #1
yannguyen
- 4
- 0
Homework Statement
When the mass M is at the position shown, it has a speed v0 = 2.17 m/s and is sliding down the inclined part of a slide. The mass reaches the bottom of the incline and then travels a distance S2 = 2.45 m along the horizontal part of the slide before stopping. The distance S1 = 1.11 m and the angle of the incline is θ = 31.1o. Calculate the coefficient of kinetic friction for the mass on the surface.
Homework Equations
E= KE + U
E+ W (ext) = 0 -> E = -W (ext) (which is the work done by frictional force)
The Attempt at a Solution
So far I've analysed the x and y components of the mass on path S1 and path S2. This is what I've got
Path S1:
y-dir: N = mgcosθ
x-dir: ƩF = -F(friction) + mgsinθ = -μmgcosθ + mgsinθ
So W1 ( work done on S1) = S1(-μmgcosθ + mgsinθ)
Path S2:
W2 = -μmg(S2)
Since -W (total) = E
W1+W2 = KE + U (at original position)
S1(-μmgcosθ + mgsinθ) - μmg(S2) = - [(1/2)mv2 + mgS1sinθ]
μ(S1gcosθ + gS2) = 2S1gsinθ + v2/2
μ = (2S1gsinθ + v2/2)/(S1gcosθ + gS2)
So far I've got μ = .105 but it's wrong!
I'd really appreciate if anyone helped me out with this cos I totally have no idea how to figure out the right answer!