- #1
MG5
- 60
- 0
Heres the problem,
A 1,440-N crate is being pushed across a level floor at a constant speed by a force of 270 N at an angle of 20.0° below the horizontal
(a) What is the coefficient of kinetic friction between the crate and the floor?
I know how to do this. The answer is .165
Heres how I solved it..
270sin20 = 92 N
270cos20 = 254 N
1440N + 92N = 1532N
Ff=uk(n)
254N=uk(1532)
uk= .165
The only thing I don't quite get is why do I use 254N, the product of 270cos20, as the Ff and why is 1532N the normal force?
Thanks.
A 1,440-N crate is being pushed across a level floor at a constant speed by a force of 270 N at an angle of 20.0° below the horizontal
(a) What is the coefficient of kinetic friction between the crate and the floor?
I know how to do this. The answer is .165
Heres how I solved it..
270sin20 = 92 N
270cos20 = 254 N
1440N + 92N = 1532N
Ff=uk(n)
254N=uk(1532)
uk= .165
The only thing I don't quite get is why do I use 254N, the product of 270cos20, as the Ff and why is 1532N the normal force?
Thanks.