Combinatorics: 16 People Seated in a Row/Circle

In summary: Then add back in the ones where both of those happen. I'm not sure if this is the right method for this problem, but it seems like it could work.In summary, there are several ways to arrange 16 people depending on the given conditions. In a row, if 4 people do not want to sit next to one another, there are 16! - 13!4! - 14!3! - 15!2! ways. If 3 people must be seated next to one another in a row, there are 14! 3! ways. In
  • #1
Finsfan342
1
0
In how many ways can 16 people be seated:

A. In a row, if 4 of the 16 do not want to sit next to one another

B. In a row, if 3 of the 16 must be seated next to one another

C. In a circle, if 3 of the 16 must be seated next to one another

D. In a circle, if 4 of the 16 do not want to sit next to one another

These are my answers,

A. 16! - 13!4! - 14!3! - 15!2!, I'm not sure if I should include the 14!3! and 15!2!

B. 14!3! +15!2!, same situation as A

C. 12!3! + 13!2!, Little confused with the circle situation

D. 15! - 12!4! - 13!3! - 14!2!
 
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  • #2
Finsfan342 said:
In how many ways can 16 people be seated:

A. In a row, if 4 of the 16 do not want to sit next to one another

B. In a row, if 3 of the 16 must be seated next to one another

C. In a circle, if 3 of the 16 must be seated next to one another

D. In a circle, if 4 of the 16 do not want to sit next to one another

These are my answers,

A. 16! - 13!4! - 14!3! - 15!2!, I'm not sure if I should include the 14!3! and 15!2!

B. 14!3! +15!2!, same situation as A

C. 12!3! + 13!2!, Little confused with the circle situation

D. 15! - 12!4! - 13!3! - 14!2!

B. Wrap the special 3 together with duct tape and consider them to be one object. You then have 14 objects to arrange, which can be done in 14! ways. But the special 3 can be arranged in 3! ways, so there are 14! 3! ways in all.

For A, I would try combining the method of B with Inclusion/Exclusion.
 

FAQ: Combinatorics: 16 People Seated in a Row/Circle

1. How many ways can 16 people be seated in a row?

There are 16! (16 factorial) ways to seat 16 people in a row. This is equal to 20,922,789,888,000 possible combinations.

2. What is the formula for calculating the number of combinations in a row?

The formula for calculating the number of combinations in a row is n! (n factorial), where n is the number of people. In this case, n=16.

3. Can you explain how to solve this problem using permutations?

Permutations are used when the order of the elements matters. In this problem, the order of the people sitting in a row matters, so we use permutations. The formula for permutations is nPr = n! / (n-r)!, where n is the total number of people and r is the number of people in each group. In this case, n=16 and r=16, so the formula becomes 16P16 = 16! / (16-16)! = 16! / 0! = 16! = 20,922,789,888,000 possible combinations.

4. What if the 16 people are seated in a circle instead of a row?

If the 16 people are seated in a circle, the formula for calculating the number of combinations changes slightly. The formula for circular permutations is (n-1)! / (n-r)!, where n is the total number of people and r is the number of people in each group. In this case, n=16 and r=16, so the formula becomes (16-1)! / (16-16)! = 15! / 0! = 15! = 1,307,674,368,000 possible combinations.

5. How do you calculate the probability of a specific person being seated in a specific seat?

The probability of a specific person being seated in a specific seat is 1/16, or 0.0625, since there are 16 total seats and each person has an equal chance of being seated in any of them.

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