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ELLE_AW
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Homework Statement
- An object of mass m=2.3±0.1kg moves at a speed of v=1.25±0.03m/s. Calculate the kinetic energy (K=1/2mv2) of the object and estimate the uncertainty δK?
Homework Equations
- Addition error propagation--> z = x + y and the Limit error--> δz = δx + δy
- Exponent error propagation --> z = xn and the Limit Error --> δz = nxn-1(δx)
- K = 1/2mv2
The Attempt at a Solution
This is what I attempted, but I really don't think it's right. I basically just included the exponent error propagation, but how does the multiplication of mv2 get incorporated?
- K = ½ mv2 = ½ (2.3kg)(1.25m/s)2 = 1.7969 kg m2 s-2 = 1.8 J
- Uncertainty of K = (m)2v1(δv) = (2.3)(2)(1.25)(0.03) = 0.1725 = 0.17
How do I combine these two rules when calculating the uncertainty of the kinetic energy?