- #1
Abigale
- 56
- 0
Hi I regard,
$$[\partial_t \Psi, \Psi]=0$$
but [itex]\Psi[/itex] is a field-operator.
I don't understand why the commutation of the derrivative of the operator [itex]\Psi[/itex] by itself should be zero?
THX
$$[\partial_t \Psi, \Psi]=0$$
but [itex]\Psi[/itex] is a field-operator.
I don't understand why the commutation of the derrivative of the operator [itex]\Psi[/itex] by itself should be zero?
THX