- #1
befj0001
- 43
- 0
$$\begin{equation}
0 = ({\rho}_m + P_m)u^{m}_iu^{m}_j + \frac{4}{3}{\rho}_ru^{r}_iu^{r}_j
\end{equation}$$
where i,j = 1,2,3 and different. That is the off-diagonal elements of the tresstensor for matter fluid and radiation fluid.
The energy conditions imply that
##\rho_m + p_m > 0## and ##\rho_r > 0##
This implies that
$$\begin{equation}
u^{m}_1=u^{m}_2=u^{m}_3=u^{r}_1=u^{r}_2=u^{r}_3=0
\end{equation}$$
But how do one conclude the last equality?
edit: Tried to write in latex-code, but it doesn't seem to work (I don't know how to do).
0 = ({\rho}_m + P_m)u^{m}_iu^{m}_j + \frac{4}{3}{\rho}_ru^{r}_iu^{r}_j
\end{equation}$$
where i,j = 1,2,3 and different. That is the off-diagonal elements of the tresstensor for matter fluid and radiation fluid.
The energy conditions imply that
##\rho_m + p_m > 0## and ##\rho_r > 0##
This implies that
$$\begin{equation}
u^{m}_1=u^{m}_2=u^{m}_3=u^{r}_1=u^{r}_2=u^{r}_3=0
\end{equation}$$
But how do one conclude the last equality?
edit: Tried to write in latex-code, but it doesn't seem to work (I don't know how to do).
Last edited: