- #1
davon806
- 148
- 1
Homework Statement
Please see the following,I am confused by the word "only".
Homework Equations
The Attempt at a Solution
I understand that the Compatibility theorem ensures we can find a basis of common eigenfunctions of [itex]\hat{A} ,\hat{B}[/itex].If each pair of eigenvalues {A_i,B_j} identifies uniquely one vector of the basis,then the set {[itex]\hat{A} ,\hat{B}[/itex]} forms a CSCO.
Here they are asserting [itex] \tilde{u_1} , \tilde{u_2} [/itex] are the only eigenstates of B in the plane.I don't see the reason for that.Could we find more orthonormal eigenstates of B in the plane spanned by the degenerate states?