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Dustinsfl
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All complex numbers of the form $(1/n) + (i/m)$, $n,m\in\mathbb{Z}^+$.Complex numbers aren't well ordered so how is this treated?
dwsmith said:All complex numbers of the form $(1/n) + (i/m)$, $n,m\in\mathbb{Z}^+$.Complex numbers aren't well ordered so how is this treated?
Complex accumulation points, also known as limit points, are points in a complex set that can be approached infinitely closely by an infinite number of other points in the set. They can be both real and imaginary numbers and are used to define open and closed sets in complex analysis.
Unlike ordinary accumulation points, which are defined in terms of epsilon neighborhoods, complex accumulation points are defined in terms of circular neighborhoods. This means that they take into account both magnitude and direction in the complex plane.
An open set in complex analysis is a set that contains all its complex accumulation points. This means that for every point in the set, there exists a circular neighborhood around that point that is fully contained within the set. In other words, the set does not include its boundary points.
A closed set in complex analysis is a set that includes all its complex accumulation points. This means that for every point in the set, there exists a circular neighborhood around that point that contains at least one point in the set. In other words, the set includes its boundary points.
Open and closed sets are defined in terms of complex accumulation points. An open set contains all its accumulation points, while a closed set includes all its accumulation points. This means that a set can be both open and closed, if it contains all its accumulation points and does not have any accumulation points outside of the set.