Complex Circuit Analysis Simplification

In summary, the conversation revolves around a circuit simulation and the process of deriving equations for U1 and U2. The suggestion to use Thevenin equivalent circuit is made and ultimately leads to the successful derivation of U1. The simulator used is called Solve Elec and can be downloaded for free.
  • #1
jonlg_uk
141
0
I have the following circuit...
circuit22.jpg


I have managed to derive an equation for U2:

u22.jpg


Now I want to substitute U2 into U1, in order to derive equation for U1

I have defined U1 as:

u11.jpg


Now I substitute U2 into the above equation. This is how far I get...I am stuck...


My circuit simulator is saying that U1 is equal to:


u11sol.jpg



However I cannot simplify to get this equation. Can someone please help I have spent hours trying to get U1 to look like the U1 that the simulator produces.


I thank you in advance.
 
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  • #2
Have you try to replace R1, R2 and E2 with his Thevenine equivalent circuit ?
Eth = R2/ ( R1 + R2 ) * E1 and Rth = R1||R2

attachment.php?attachmentid=43692&stc=1&d=1328795691.jpg


V3 = I * R3

[tex] I = \frac{Eth}{\sqrt{(Rth + R3)^2 + Xc^2)}} = \frac{E1*\frac{R2}{R1+R2}}{\sqrt{(R1||R2 + R3)^2 + Xc^2)}} [/tex]

And

[tex] V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}} [/tex]
 

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  • #3
Jony130 said:
Have you try to replace R1, R2 and E2 with his Thevenine equivalent circuit ?
Eth = R2/ ( R1 + R2 ) * E1 and Rth = R1||R2

attachment.php?attachmentid=43692&stc=1&d=1328795691.jpg


V3 = I * R3

[tex] I = \frac{Eth}{\sqrt{(Rth + R3)^2 + Xc^2)}} = \frac{E1*\frac{R2}{R1+R2}}{\sqrt{(R1||R2 + R3)^2 + Xc^2)}} [/tex]

And

[tex] V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}} [/tex]

No I haven't tried this before, but I did just try it and I still can't derive U1. Perhaps I am being stupid...
 
  • #4
A made a small error instead of V3 I should write U1

jonlg_uk said:
IMy circuit simulator is saying that U1 is equal to:
u11sol.jpg
What is the name of your simulation program?
 
  • #5
Thanks for your help Jony, the simulator is giving me this equation:

u11sol.jpg


I haven't derived that myself^. When I expand out the equation you derived:


[tex] V3 = \frac{E1*R2*R3}{(R1+R2)\sqrt{(R1||R2 + R3)^2 + Xc^2)}} [/tex]

I still not can get a the equation looking like the simulator one.


BTW the simulator is called Solve Elec, you can download it for free.

[URL="http://www.physicsbox.com/indexsolveelec2en.html[/URL]
 
Last edited by a moderator:
  • #6
Ah done it! you are right I was being stupid. I am upset with myself that I never thought to do a thevin equivalent :( thanks a lot for your help. I can sleep peacefully tonight.
 

FAQ: Complex Circuit Analysis Simplification

What is complex circuit analysis simplification?

Complex circuit analysis simplification is a process of reducing a complicated electrical circuit into an equivalent and simpler circuit, while maintaining the same behavior and characteristics.

2. Why is it important to simplify complex circuits?

Simplifying complex circuits allows for easier understanding and analysis of the circuit. It also helps in identifying potential problems and finding efficient solutions. Additionally, simplified circuits are easier to troubleshoot and modify.

3. What are some common techniques used for simplifying complex circuits?

Some common techniques for simplifying complex circuits include Kirchhoff's laws, Thevenin's theorem, and Norton's theorem. These methods involve replacing sections of the circuit with equivalent components or simplifying the circuit using algebraic equations.

4. How do you know when a circuit is simplified enough?

A circuit is simplified enough when it cannot be reduced any further using the available techniques without changing its behavior or characteristics. This is usually achieved when all components are connected in a series or parallel configuration.

5. Can simplifying a circuit affect its performance?

In most cases, simplifying a circuit does not affect its performance as long as the equivalent circuit maintains the same voltage, current, and resistance values. However, in some cases, simplifying a circuit may result in a slight change in the circuit's behavior, which should be carefully considered before making any modifications.

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