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eng_stud
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Homework Statement
consider a circuit expressed by [tex]v(t)= 100cos \omega t[/tex]
and [tex] i(t)=2cos(\omega t+\pi / 3) [/tex] .
Find the reactance.
Homework Equations
[tex]Z=\frac{V}{I} = R+jX[/tex]
The Attempt at a Solution
[tex]Z=\frac{100}{2\angle \pi /3} = 50\angle -\pi /3 = 46 - j19[/tex]
Does the negative imaginary part mean there is simply more reactance from the capacitor than inductor? Or *only* cap?
thanks!
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