Complex Logarithm: Solving tan-1[(2sqrt(3) - 3i)/7]

In summary, the task is to find the value of tan-1[(2sqrt(3) - 3i)/7] using the given equation tan-1z = (1/2i)ln[(1+iz)/(1-iz)]. The attempt at a solution involves rewriting the expression inside the logarithm in the form a+bi and using complex conjugates to find its magnitude and angle. The current attempt has a sign error and further calculations are needed to find the final solution.
  • #1
metgt4
35
0

Homework Statement



If

tan-1z = (1/2i)ln[(1+iz)/(1-iz)]

then find

tan-1[(2sqrt(3) - 3i)/7]



The Attempt at a Solution



I haven't gotten very far, but this is what I have so far:

tan-1[(2sqrt(3) - 3i)/7]

= (1/2i)ln[(i2sqrt(3) + 10)/(i2sqrt(3) + 4)]

Where do you go from there? I'm not completely familiar with the rules of complex logarithms. Can you split it into real and imaginary parts?
 
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  • #2
You should check what you already have. I think you've already got a sign wrong. But you want write the expression inside the log in the form a+bi with a and b real, so you can find it's magnitude and angle. You know how to do that with a ratio using complex conjugates, right?
 

FAQ: Complex Logarithm: Solving tan-1[(2sqrt(3) - 3i)/7]

1. What is the definition of a complex logarithm?

A complex logarithm is a mathematical function that calculates the logarithm of a complex number. It is defined as the inverse of the exponential function, and can be written as logb(z) = x + iy, where z is the complex number, b is the base of the logarithm, and x and y are real numbers.

2. How do you solve for a complex logarithm?

To solve for a complex logarithm, you can use the formula logb(z) = x + iy. First, convert the complex number into polar form (r(cosθ + isinθ)). Then, apply the formula logb(z) = logb(r) + iθ. Finally, use the properties of logarithms to simplify the equation and find the values of x and y.

3. What is the meaning of tan-1 in the expression tan-1[(2sqrt(3) - 3i)/7]?

Tan-1 (also written as arctan) is the inverse trigonometric function for tangent. In this expression, it is used to find the angle whose tangent is equal to the complex number (2sqrt(3) - 3i)/7.

4. How do you solve for the complex logarithm of a complex number?

To solve for the complex logarithm of a complex number, you can follow the same steps as solving for a real logarithm. First, convert the complex number into polar form. Then, apply the formula logb(z) = logb(r) + iθ. Finally, simplify the equation using properties of logarithms and solve for the values of x and y.

5. What is the significance of solving for tan-1[(2sqrt(3) - 3i)/7] in the complex logarithm?

Solving for tan-1[(2sqrt(3) - 3i)/7] in the complex logarithm allows you to find the angle whose tangent is equal to the complex number (2sqrt(3) - 3i)/7. This is useful in many applications, such as in engineering, physics, and signal processing.

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