Complex mapping z ↦ ω = (z − a)/(z − b)

In summary, the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) transforms the complex plane by taking a point \( z \) and mapping it to a new point \( \omega \) based on the locations of points \( a \) and \( b \). This transformation is significant in complex analysis as it represents a Möbius transformation, which preserves angles and circles, and can be used to analyze the behavior of complex functions.
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Hill
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Homework Statement
Consider the complex mapping ##z \mapsto \omega = \frac {z - a} {z - b}##. Show geometrically that if we apply this mapping to the perpendicular bisector of the line-segment joining a and b, then the image is the unit circle. In greater detail, describe the motion of ω round this circle as z travels along the line at constant speed.
Relevant Equations
geometry
All points on that line are equidistant from the points a and b. Thus, the length of ##\frac {z - a} {z - b}## is 1, i.e., the points on the unit circle.
If the angle of ##z - a## is ##\alpha##, and the angle of ##z - b## is ##\beta##, then the angle of ##\frac {z - a} {z - b}## is ##\alpha - \beta##. If the point z is far toward either end of the line, ##\alpha - \beta## is close to zero. If z is in the midpoint between a and b, ##\alpha - \beta = \pi##. Thus, as z travels along the line from one "end" to another, w starts near 1, moves along one half of the unit circle speeding up towards -1, and then slows down again as it continues on the other half of the unit circle toward 1.
Are there other geometric details that I've missed?
 
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This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
 
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FactChecker said:
This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
Thank you. I see that the next chapter in the textbook is "Möbius Transformations and Inversion."
 
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I personally liked and was impressed by your proof. I think it is the right kind of reasoning to understand analytic functions of a complex variable. Of course, if you have theorems that can be used, that is the first thing to look for. But without applicable theorems, your kind of analysis is good.
 
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FAQ: Complex mapping z ↦ ω = (z − a)/(z − b)

What is complex mapping in the context of \( z \mapsto \omega = \frac{z - a}{z - b} \)?

Complex mapping refers to the transformation of complex numbers from one form to another. In the context of \( z \mapsto \omega = \frac{z - a}{z - b} \), it involves mapping a complex number \( z \) to another complex number \( \omega \) using the given formula, where \( a \) and \( b \) are constants in the complex plane.

What is the significance of the constants \( a \) and \( b \) in the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \)?

The constants \( a \) and \( b \) determine the specific transformation applied to the complex number \( z \). The value \( a \) represents a shift in the complex plane, while \( b \) affects the scaling and rotation of the mapping. These constants essentially control the behavior and properties of the transformation.

What happens to the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) when \( z = b \)?

When \( z = b \), the denominator of the mapping \( \frac{z - a}{z - b} \) becomes zero, causing the mapping to become undefined. This indicates a singularity at \( z = b \), where the transformation cannot be applied.

How does the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) affect the geometric properties of the complex plane?

The mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) can be interpreted geometrically as a Möbius transformation, which can map circles and lines in the complex plane to other circles and lines. It preserves the angles between curves but can change their size and position, leading to distortions in the plane.

Can the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) be inverted, and if so, what is the inverse mapping?

Yes, the mapping \( z \mapsto \omega = \frac{z - a}{z - b} \) can be inverted, provided \( \omega \neq \frac{a - b}{0} \). The inverse mapping is given by \( \omega \mapsto z = \frac{b \omega + a}{\omega + 1} \), which allows us to retrieve the original complex number \( z \) from \( \omega \).

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