Complex Number Exponentiation: Finding the Power of z^23 for z = 1+1

[Ry122]

Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i8pie)
But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
should be 2^(23/2) not 2^(16)

 

[Tedjn]

You're right, of course. I don't know from where the book got 2¹⁶.

 

[tiny-tim]

… 32 ≠ 23 …

Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i*pie)

Hey guys!

It's obviously z^32 …

(btw, if you type alt-p, it prints π)