- #1
- 352
- 88
If you have a 2-D vector in polar coordinates (a magnitude R and an angle theta) you can convert it to Cartesian coordinates with the following equation:
[tex]x + yi = R e^{\theta i}[/tex]
Or from Cartesian to polar by:
[tex](R,\theta) =ln (x + yi) [/tex]
Why does this work? I just can't quite envision this. cosh and sinh have a similar relationship in that you could almost treat them as trig functions even though they're based on e.
[tex]x + yi = R e^{\theta i}[/tex]
Or from Cartesian to polar by:
[tex](R,\theta) =ln (x + yi) [/tex]
Why does this work? I just can't quite envision this. cosh and sinh have a similar relationship in that you could almost treat them as trig functions even though they're based on e.