Complex Variables: Proving 1+2w+3w^2+...+nw^(n-1) = n/(w-1)

In summary: Now, using A, we know that 1+2w+...+(n-2)w^(n-2) = (n-1)/(w-1). So we can substitute this in the first term and simplify:w[(n-
  • #1
jjangub
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Homework Statement


Let w = e^((2pi*i)/n). Show that 1+2w+3w^2+...+nw^(n-1) = n/(w-1)


Homework Equations


1+x+x^2+x^3+...+x^m = (1-x^(m+1))/(1-x) --> A
1+x+x^2+x^3+... = 1/(1-x) --> B

The Attempt at a Solution


First of all, multiply (w-1) on both sides, then we get
w+2w^2+3w^3+...+(nw^n)-1-2w-3w^3-...-nw^(n-1) = n we simplify left side,
-1-w-w^2-w^3-...-w^n+(nw^n) = n add -1 on both sides
1+w+w^2+w^3+...+w^n-(nw^n) = -n
1+w+w^2+w^3+...+w^n = (nw^n)-n for the left side, we know from A that
(1-w^(n+1))/(1-w) = (nw^n)-n
But I can't get left side and right side equal.
Did I use the right method? Which part is wrong?
Please tell me...
Thank you
 
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  • #2
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Hello, thank you for your question. Your approach is correct, but there is a small error in your simplification. Let's start from where you simplified the left side:

-1-w-w^2-w^3-...-w^n+(nw^n) = n

You correctly added -1 on both sides, but then you made a mistake in the next step. The term -nw^(n-1) should be -nw^n. So the correct simplification is:

-1-w-w^2-w^3-...-w^n+(nw^n) = n
-1-w-w^2-w^3-...-w^n-(nw^(n-1)) = n

Now, you can continue with your approach:

1+w+w^2+w^3+...+w^n-(nw^n) = -n
(1+w+w^2+w^3+...+w^n)/(1-w) = -n/(1-w)
Using B, we can simplify the left side to 1/(1-w) and we get:
1/(1-w) = -n/(1-w)
1 = -n
Which is obviously not true. So where did we go wrong?

The mistake is in the step where we simplified -nw^(n-1) to -nw^n. This is only true if n is an even number. When n is an odd number, we cannot simplify -nw^(n-1) to -nw^n. So, in order to make our approach work for both even and odd numbers, we need to consider two cases:

Case 1: n is an even number.
In this case, we can simplify -nw^(n-1) to -nw^n and continue with our approach as shown above.

Case 2: n is an odd number.
In this case, we need to use a different approach. We can start from the original equation:

1+2w+3w^2+...+nw^(n-1) = n/(w-1)

Multiply both sides by (w-1):

(1+2w+3w^2+...+nw^(n-1))(w-1) = n

Expand the left side and simplify:

w+2w^2+...+nw^(n-1)-1-2w-3w^2-...-nw^(n-1) = n
w+2
 

FAQ: Complex Variables: Proving 1+2w+3w^2+...+nw^(n-1) = n/(w-1)

1. What are complex variables?

Complex variables are numbers that include both a real part and an imaginary part. They are represented in the form a + bi, where a is the real part and bi is the imaginary part (i is the imaginary unit).

2. What does the notation "1+2w+3w^2+...+nw^(n-1)" mean?

This notation represents a sum of terms where each term is multiplied by an increasing power of a complex variable w. For example, in the expression 1+2w+3w^2, the first term is multiplied by w^0, the second term by w^1, and the third term by w^2.

3. How do you prove the equation 1+2w+3w^2+...+nw^(n-1) = n/(w-1)?

To prove this equation, we can use mathematical induction. First, we prove the equation is true for n=1. Then, assuming the equation is true for n=k, we prove it is also true for n=k+1. This will show that the equation holds for all positive integers n.

4. Why is it important to prove this equation?

This equation is important because it is a fundamental result in complex analysis and has many applications in mathematics and physics. It also helps to understand the behavior of complex numbers and their properties.

5. Are there any limitations to this equation?

Yes, the equation only holds for complex numbers where w is not equal to 1. If w=1, then the denominator in the equation becomes 0, which is undefined. Additionally, the equation only holds for positive integers n.

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