Complexes and Reals: The Impossibility of an Onto Ring Homomorphism

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An onto ring homomorphism from the Complex numbers to the Real numbers is impossible due to the fundamental properties of these number systems. The Complex numbers guarantee the existence of square roots for all elements, including negative numbers, while the Reals do not. If such a homomorphism existed, it would lead to contradictions, such as mapping a square root of -1 to a Real number, which is not feasible. Specifically, if f(z) = -1 for some z in the Complex numbers, then f(a) would have to yield a square root of -1, which cannot exist in the Reals. Therefore, the structural differences between the two sets prevent the existence of an onto ring homomorphism.
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Onto ring homomorphism C-->R

Why can't there be an onto ring homomorphism from the Complexes to the Reals?

The only property of the complexes that the rations don't have that I can think of is the guarantee of square roots- but I can't see how that would interfere with an onto function.
 
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Let f be an onto homomorphism. Let z be such that f(z)=-1. Consider a such that a²=z, then f(a)²=f(z)=-1. This can't happen...
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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