Complimentary Angles: Understand Why sin(90-theta) = cos theta

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Complementary angles are defined as two angles that sum to 90 degrees. The relationship sin(90-theta) = cos(theta) arises from the properties of right triangles, where the sine of one angle equals the cosine of its complementary angle. This is illustrated by the ratios of the sides in a right triangle, where sin(B) and cos(A) represent the same ratio of opposite to hypotenuse. The confusion often stems from not clearly understanding the definitions and relationships of the angles involved. Understanding this relationship is crucial for solving problems involving trigonometric functions.
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Homework Statement


It bascially says when the sum of two angles are 90 deg they are complimentary...
Then it goes on saying
sin(90-theta) = cos theta
and so on...

I understand the concept such as if sin(30) = cos(60)
But the book doesn't explain why it works.. it just says if two compl angles are 90 deg then sin(90-theta) = cos theta, which is not an explanation at all...
can some one help me understand why this is?

Thank you.



Homework Equations





The Attempt at a Solution

 
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Miike012 said:
I understand the concept such as if sin(30) = cos(60)
First of all, you forgot the degree marks. If you write "sin(30) = cos(60)", I'm assuming you meant radian measure. You must write sin (30°) = cos (60°). Secondly, If you "understood" the concept above, then why are you asking it in the first place? Sounds like you really don't understand.

Look at this diagram:
[PLAIN]http://home.comcast.net/~yeongil/images/RtTri.jpg
In a right triangle, the two non right-angles have to be complements of each other.
\sin B = \frac{opp}{hyp} = \frac{b}{c}
and
\cos A = \frac{adj}{hyp} = \frac{b}{c}
so
\sin B = \cos A.
Since B = 90° - A,
\sin (90^{\circ} - A) = \cos A.
 
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