- #1
unseenfootage
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Homework Statement
Hello fellow Physics Forumers
My first post and , hopefully not my last. I've been lurking for a long while and the tempo has increased since I started my 1st year engineering course last semester.
So I decided to register today as I have a bit of a puzzle.
We have a project to construct a truck which will be used in a torque/speed test.
First we have to do a speed - torque test of a small 1.5v/3v motor using a gear ratio (output shaft speed/motor speed) of 1/256.
I have the following kit:
http://www.mfacomodrills.com/gearboxes/multiratio.jpg
The motor is 1.5-3.0v with 8200 rpm and 14000 rpm respectively.
The driver gear has 12 teeth.
There are 6 compound gears with 48 outer and 12 inner teeth.
Two shafts , one with pulley
Assembly kit.
My question is how to achieve the gear ratio (output shaft speed/motor speed) of 1/256, with what I have?
Kind regards.
Homework Equations
Gear ratio = (No. Teeth on gear B/No. Teeth on gear A) * (No. Teeth on gear D/No. Teeth on gear C) * (No. Teeth on gear F/ No. Teeth on gear E) * (No. Teeth on gear H/No. Teeth on gear G).Gear A is the driver gear with 12 teeth. The rest are compound gears with 48 outer and 12 inner teeth.
The Attempt at a Solution
48/12 * 48/12 * 48/12 * 48/12
= 4 * 4 * 4 * 4
=256
This appears to be the solution, except I only have two shafts and the assembly plate seems to have only space for two shafts.
Is there a way of assembling it (maybe 2 gears per shaft) which might work?
Kind regards...