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typeinnocent
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Homework Statement
If the maximum kinetic energy given to the electrons in a Compton scattering experiment is 10 keV, what is the wavelength of the incident X-Rays?
Homework Equations
[tex]\Delta[/tex][tex]\lambda[/tex] = (h/mc)*(1-cos[tex]\theta[/tex])
E = hc/[tex]\lambda[/tex]
[tex]\Delta[/tex][tex]\lambda[/tex] = [tex]\lambda[/tex]scattered - [tex]\lambda[/tex]incident
[c]3. The Attempt at a Solution [/b]
I think I made this question more complex than it is...
So I know that [tex]\Delta[/tex][tex]\lambda[/tex] = .00243 nm and Einitial=Ephoton + Eelectron, and Eelectron =10 keV.
I made [tex]\lambda[/tex]scattered = hc/Ephoton.
This equals [tex]\Delta[/tex][tex]\lambda[/tex] = hc/(Einitial - 10 keV), and then I plugged hc/[tex]\lambda[/tex]incident for Einitial.
My final equation is .00243 - [tex]\lambda[/tex]incident = 1240 eVnm/(hc/[tex]\lambda[/tex]incident - 10 kEv).
The solution is .0239 nm, however the correct answer in the book is .022 nm.
Although the solution is close, I feel that it's more due to luck than to actually doing the correct methodology. Could anyone help me solve this problem? Thanks!