Compton Scattering - Find x component of electron momentum

In summary: For example, to state a momentum is '4.98 x 10-23' is incomplete: is that in units of g.cm/s, or lbs.ft/s, or something else?
  • #1
JoeyBob
256
29
Homework Statement
See attached
Relevant Equations
p=h/wavelength
So I can find the initial momentum using p=h/wave = 4.98 x 10-23. Now my problem is that I don't know the final momentum of the photon nor electron, I just know the photon is scattered at an angle of 34 degrees.

I know how to solve this problem if I was given the final wavelength of the light, but that's not given.

p initial = cos(34)* mag. of photon momentum + x component of electron momentum

From the above equation all I need is the final magnitude of the momentum of the photon. Since the final wavelength is not given idk how to find this. If the velocity or kinetic energy of the electron was given I could use energy conservation to find the answer, but that's not given either.

I just don't understand how to calculate the final momentum of the photon if no final wavelength is given.
 

Attachments

  • question.PNG
    question.PNG
    7.9 KB · Views: 135
Physics news on Phys.org
  • #2
;
JoeyBob said:
I just don't understand how to calculate the final momentum of the photon if no final wavelength is given.
Have you solved this yet? If not, see the formula you stated in post #7 in your other thread: https://www.physicsforums.com/threads/compton-scattering-determine-momentum.1001734/

Also, you can easily avoid losing marks in exams/assignments by including the correct units with values. For example to state a momentum is '4.98 x 10-23' is incomplete: is that in units of g.cm/s, or lbs.ft/s, or something else?
 
  • #3
Steve4Physics said:
;
Have you solved this yet? If not, see the formula you stated in post #7 in your other thread: https://www.physicsforums.com/threads/compton-scattering-determine-momentum.1001734/

Also, you can easily avoid losing marks in exams/assignments by including the correct units with values. For example to state a momentum is '4.98 x 10-23' is incomplete: is that in units of g.cm/s, or lbs.ft/s, or something else?

I mean I thought I understood it since I was able to use momentum or energy to solve the problem you cite in that thread. The issue here is I don't have the final wavelength so nothing seems to work.

Units are what I use as a last resort and don't always help. Trying to cancel them out units to give the units of the answer ect.
 
  • #4
JoeyBob said:
I mean I thought I understood it since I was able to use momentum or energy to solve the problem you cite in that thread. The issue here is I don't have the final wavelength so nothing seems to work.

Units are what I use as a last resort and don't always help. Trying to cancel them out units to give the units of the answer ect.
In post #7 of https://www.physicsforums.com/threads/compton-scattering-determine-momentum.1001734/ you wrote “change in wavelength = (h/mc)(1-cos(angle)”.

You got the brackets wrong, but you can sort this out.

Use your formula to find the change in wavelength. Then add this to the initial wavelength. This gives you the final wavelength.

Units are not ‘a last resort’. It is incorrect to state a value without correct units. Like saying “This piece of string is 15 long”. Also, it creates a very poor impression when someone sees it - and it will cost you marks in examinations. Your decision!

Edit. I don't mean puitting units into equations. I mean including the units when stating single values.
 
Last edited:
  • Like
Likes JoeyBob

FAQ: Compton Scattering - Find x component of electron momentum

What is Compton Scattering?

Compton Scattering is a phenomenon in which a photon collides with an electron, resulting in the transfer of energy and momentum from the photon to the electron.

How is the x component of electron momentum calculated in Compton Scattering?

The x component of electron momentum can be calculated using the formula px = h/λ - h/λ', where h is the Planck's constant, λ is the initial wavelength of the photon, and λ' is the final wavelength of the scattered photon.

What is the significance of finding the x component of electron momentum in Compton Scattering?

The x component of electron momentum is important because it allows us to determine the direction and magnitude of the electron's motion after the collision with the photon. This information is crucial in understanding the behavior of particles at the atomic level.

How does the x component of electron momentum change with different initial and final wavelengths in Compton Scattering?

The x component of electron momentum increases as the difference between the initial and final wavelengths increases. This means that the electron's motion becomes more energetic and its direction changes more significantly.

Can the x component of electron momentum be negative in Compton Scattering?

Yes, the x component of electron momentum can be negative in Compton Scattering. This indicates that the electron is moving in the opposite direction of the initial photon's motion after the collision.

Similar threads

Back
Top