- #1
lordkelvin
- 22
- 0
The unit normal vector N of a given curve is equal to the first derivative with respect to t of the unit tangent vector T'(t)divided by the norm of T'(t) (For a parametric vector equation of parameter t.)
I realize this works because T(t) is orthogonal to T'(t), but I don't understand why the derivative of the vector T is orthogonal to T itself.
Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.
I realize this works because T(t) is orthogonal to T'(t), but I don't understand why the derivative of the vector T is orthogonal to T itself.
Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.